The vapour density of a mixture of NO2 and N2O4 is 38.3 at 26.7 oC. Calculate the number of
moles of NO2 in 100 g of the mixture.
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Answer:
Let the total number of moles = 1
let the number of moles of NO2 = X
so number of moles of N2O4 = 1 -x
molar mass of mixture = 2 x vapour density
= 2 × 38.3 = 76.6
Now x × 46 + ( 1-x) 92 = 76.6
46 x + 92 -92 X = 76.6
46 x = 15.4
x = 15.4 / 46 = 0.335
% age of NO2 = 33.5 %
% age of N2O4 = 66.5 %
Number of moles NO2 in 100 g of mixture =0.335 × 100 / 76.6 = 0.437
Explanation:
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