the vapour density of a volatile chloride of divalent metal is 59.5 and eq(m) will be
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valency=[tex] \frac{2*v.d.}{em(m)+35.5}
here v.d.=vapour density em(m)=equivalent mass of metal[/tex] and 35.5 is eq mass of cl.
2=2*59.5/x+35.5
x+35.5=59.5
x=24.0
2=2*59.5/x+35.5
x+35.5=59.5
x=24.0
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The vapour density of a volatile chloride of divalent metal is 59.5 and eq(m)=24g
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