Question

the vapour density of a volatile chloride of divalent metal is 59.5 and equivalent mass of the metal is what ?
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Answer 1

Answer:

Molecular formula of the compound is MCl2, where M is the divalent cation.

Vapour density (D) = Molecular mass (M) /2

So molar mass of the compound = 2 x 59.5 = 119

Equivalent mass (E) = molar mass (M) / (number of cation x valency)

Number of cation = 1, and valency of the cation =2

So, E = 119 / (1x2) = 59.5

Answer 2

Answer:

24

Explanation:

Molecular mass = 2xVapour density

molecular mass = 119

equivalent weight of the compound:

the metal is divalent , Let the metal be X ,then the formula will be X(Cl)2, because the metal is divalent.

equivalent mass = 119/total charge of cations or anions(2)

equivalent mass of the compound= 59.5

equivalent mass of chlorine = 35.5/1 [1 is the valency of the element chlorine]

equivalent mass of the metal = total equivalent mass - equivalent mass of chlorine

equivalent mass of the metal = 59.5 - 35.5 = 24

therefore the equivalent mass of the metal is 24