THE VAPOUR DENSITY OF A VOLATILE CHLORIDE OF METAL IS 59.5 AND EQUIVALENT MASS OF THE METAL IS 24 WHAT IS THE ATOMIC ,MASS OF ELEMENT
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WHAT IS THE ATOMIC MASS OF ELEMENT IN ABOVE QUESTION
THE VAPOUR DENSITY OF A VOLATILE CHLORIDE OF METAL IS 59.5 AND EQUIVALANT MASS OF THE METAL IS 24 THEN WHAT IS ATOMIC MASS OF ELEMENT
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V.D.= Molecular Weight /2
Here we have V.D.= 59.5
the Molecular Weight=V.D.*2
Molecular weight=59.5*2
Molecular weight=119g
Here we have V.D.= 59.5
the Molecular Weight=V.D.*2
Molecular weight=59.5*2
Molecular weight=119g
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