Physics, asked by ShuchiRecites, 10 months ago

The vapour density of a volatile chloride of metal is 96 and specific heat of metal is 0.13 cal/g. The equivalent weight of metal will be? (Approximately)

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Answers

Answered by Anonymous
10

\huge\mathsf{\red{Answer:-}}

वाष्पशील क्लोराइड का कोई आणविक भार

= 2... 95

= 190

MClX=क्लोराइड का सूत्र

एम = 6.4 / 0.13 का अनुमानित वजन

= 49.23

= 49.23 + x =35.5

= 190

x = 140.77 / 35.5

= 3.96 = 4

= 49.23 / 4 = 12.3

Not sure do my answer hope it helps you!

जवाब के बारे में सुनिश्चित नहीं हूँ आशा है कि यह आपकी मदद करता है !!


ShuchiRecites: From where this 6.4 came?
Anonymous: answer wrong?
ShuchiRecites: correct :-)
Anonymous: :)
Answered by aparajitha2006ap
1

ANSWER

49.23/4

= 12/3

THANKS A TON

HOPE IT HELPS

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