the vapour density of air is 14.46 and it contains 23% oxygen by mass. Calculate the number of molecules of oxygen present in 1.12 L of Air at NTP.
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Answer:
1 L of air contains 21 % of oxygen i.e; 0.21L of oxygen.
At STP 1 mole =22.4L
Therefore,
No. of moles of o
2
at 0.21L
→
22.4
0.21
=0.0094 moles
Therefore;
5L of air contains, 5∗0.0094 moles
→0.0462→4.68∗10
−2
moles
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