Question

the vapour density of pure ozone is

Answer 1

Heya frnd : )

Here u get ur answer :-

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The vapour density of ozone is 24.


☆☆ VAPOUR DENSITY ☆☆

Vapour density is the density of a gas with respect to the density of hydrogen, at the same temperature and pressure.

♢ It is given by:

Vapour density = Density of the gas / Density of hydrogen.

Vapour density of ozone = 48 / 2.016
Vapour density of ozone is = 23.809
Vapour density of ozone ~= 24

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THANK YOU
@SRK6

Answer 2

The vapour density of pure ozone is 24.

Ozone is an inorganic molecule and also called as trioxygen.

Ozone molecular formula is ${ O }_{ 3 }$.

It is present in pale blue coloured gas and it has pungent smell.

Molecular weight of oxygen is 16 g/mol

$Molar\quad mass\quad of\quad ozone\quad is\quad 3\quad \times \quad 16\quad g/mol\quad =\quad 48\quad g/mol$

We know,

               $Molecular\quad weight\quad =\quad 2\quad \times \quad vapour\quad density$

               $48\quad =\quad 2\quad \times \quad vapour\quad density$

               $Vapour\quad density\quad =\quad \frac { 48 }{ 2 } \quad =\quad 24$