the vapour pressure in mm of hg,of an aqueous solution obtained by adding 18g of glucose to 180g of water at 100 degree is
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At 100
o
C, the vapour pressure of water,
P
0
=760 mm Hg = atmospheric pressure.
The molar masses of glucose and water are 180 g/mol and 18 g/mol respectively.
Number of moles of glucose =
180
18
=0.1
Number of moles of water =
18
180
=10
Mole fraction of glucose X=
10+0.1
0.1
=0.0099
Let P mm be the vapour pressure of solution
P
o
P
o
−P
=X
760
760−P
=0.0099
760−P=7.524
P=752.4 mm Hg
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