the vapour pressure of 2.1 % of an aqua solution of non volatile solute at 373 kelvin is 755 mm HG calculate the molar mass of solute
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P° A = 760 mmHg
(P° A-P A) / P° A = xB
= (760 - 755) / 760
= 0.0065789
m water = 100 - 2.1 = 97.9 g
n water = 97.9/18 = 5.4389 moles
xB = nB/(nA+nB)
0.0065789 = nB/(nB+5.4389)
nB = 0.036019
Molar mass = m/nB
= 2.1 / 0.036019
= 58.303 g.
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