The vapour pressure of 98%aqueous solution of A is 700 mm of Hg at 373K.Thus the M.w. of A is
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mass of solute = 2g
mass of solvent = 98g
molar mass of solvent = 18 g/mol
vapour pressure = 700mm of Hg
temperature = 373K
vapour pressure of pure water at 373K = 760 mm of Hg
vp(vapour pressure) of pure solvent - vp of solution = change in vp
760 - 700 = 60 mm of Hg
molar mass of solute = mass of solute × molar mass of solvent/ mass of solvent (vp of pure solvent/ change in vp)
m = 2×18/98(760/60)
m = 4.5 g/mol
Explanation:
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