Question

The vapour pressure of 98%aqueous solution of A is 700 mm of Hg at 373K.Thus the M.w. of A is​

Answer 1

Answer:

mass of solute = 2g

mass of solvent = 98g

molar mass of solvent = 18 g/mol

vapour pressure = 700mm of Hg

temperature = 373K

vapour pressure of pure water at 373K = 760 mm of Hg

vp(vapour pressure) of pure solvent - vp of solution = change in vp

760 - 700 = 60 mm of Hg

molar mass of solute = mass of solute × molar mass of solvent/ mass of solvent (vp of pure solvent/ change in vp)

m = 2×18/98(760/60)

m = 4.5 g/mol

Explanation:

hope it helps you mate

please follow