Question

The vapour pressure of a certain pure liquid A at
298 K is 40 m bar. When a solution B is prepared in
A at the same temperature, the vapour pressure is
found to be 32 m bar. The mole fraction of A in the
solution is :
​

Answer 1

Answer:

0.8

Explanation:

by using Roults law

P(total A+B) = p(of A) × mole fraction

32= 40 × X

X= 0.8