Chemistry, asked by mdsarfarz72500, 7 months ago

the vapour pressure of a pure liquid at 25 C is 100 mm hg calculate relative lowering

Answers

Answered by haripkr

2

Answer:

Explanation:

P

0

=100mm Hg

Relative lowering of vapor pressure (P−P

0

)=x×P

0

=0.8×100mm Hg=80mm Hg

Therefore, the relative lowering of vapor pressure is 80 mm of Hg.

Answered by dolisindhu159

1

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