Question

The vapour pressure of a pure solvent at a certain temperature is 0.0227 bar.What is a vapour pressure of a solution containing 6g of solute in 50 g of solvent ??

Answer 1

..

Explanation:

p

0

p

0

−p

=

W

1

M

2

W

2

M

1

p

0

=0.850bar= vapour pressure of pure benzene.

p=0.845bar= vapour pressure of solution.

W

1

=39g= mass of benzene

W

2

=78g= mass of solute

M

1

=78g/mol= Molar mass of benzene.

M

2

= Molar mass of solute.

0.850bar

0.850bar−0.845bar

=

39g×M

2

0.5g×78g/mol

M

2

=170g/mol

Answer 2

This is the answer

I think so