Question

the vapour pressure of a saturated solution of a sparingly soluble salt (A2B3) is 31.8mm Hg at 40°C. If the vapour of pure water is 31.9mmHg, the solubility product (Ksp) of A2B3 at the same temperature will be​

Answer 1

Answer:

Let stability of A

2

B

2

be 5 moles/litre

A

2

B

2

⇌2A

+

+2B

−

2s 2s

K

sp

=(2s)

2

×(2s)

2

=16×s

4

Now,

P

P

o

−P

=

N

n

=

55.56

4

⇒

31.8

31.9−31.8

=

55.56

4s

⇒S=0.043 moles/litre

∴K

sp

=16×(0.043)

4

=5.47×10

−5