Question

The vapour pressure of a solution prepared by dissolving 1 mol of liquid A and 2 mol of liquid B has bond found to be 38 torr. The vapour pressure of pure A and pure B are 45 and 36 torr respectively. The solution

A

Shows negative deviation

B

Is a minimum boiling azeotrope

C

Is an ideal solution

D

Has ∆H ke positive​

Answer 1

Answer:

shows negative deviation

Explanation:

total is 38 and individual is 36 and 46 torr now we know that from the curve that the curve becomes negative due to less less individual vapour pressure.

AND I AM SORRY I COULDNT GIVE THE PIC OF THE CURVE BUT I AM SURE U CAN FIND IT IN THE INTERNET.