Question

The vapour pressure of a solvent. A is 0.80 atm.
When non-volatile substance B is added to this
solvent, its vapour pressure drops to 0.6 atm. The
mole fraction of B in the solution is
[a] 0.25​

Answer 1

Answer:

this is the answer in the Pardeep book chapter 2 solution 0.95667

Answer 2

Answer:

Using Raoults law for lowering of vapour pressure.We get PoPo−P=x2

putting,Values of actual and lowered vapour pressure we get

0.80.8−0.6=x2

where x2 is the mole fraction 

Ans-0.25           

Explanation:

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