The vapour pressure of an aqueous solution containing 2.00 g of rock salt in 100 g of water has a vapour pressure of 751 torr and 373 k. the degree of ionisation of rock salt in the solution is
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Utilize Raoult's Law to decide mole portion of the dissolvable:
Psolution = (χsolvent) (P°solvent)
755 torr = (χsolvent) (2.1 torr)
χsolvent = 755 torr/2.1torr
χsolvent = 359.5
2) Use the mole portion and the moles of electrolyte to decide the moles of Z:
100. g/18.015 g/mol = 5.55093 mol
0.99276316 = 5.55093/(5.55093 + x)
x = 0.040464 mol
3) Calculate molar mass of Z:
359.5/0.040464 mol = 8.975 g/mol
Psolution = (χsolvent) (P°solvent)
755 torr = (χsolvent) (2.1 torr)
χsolvent = 755 torr/2.1torr
χsolvent = 359.5
2) Use the mole portion and the moles of electrolyte to decide the moles of Z:
100. g/18.015 g/mol = 5.55093 mol
0.99276316 = 5.55093/(5.55093 + x)
x = 0.040464 mol
3) Calculate molar mass of Z:
359.5/0.040464 mol = 8.975 g/mol
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