Question

The vapour pressure of pure liquid a is 0.80 atm on mixing and nonvolatile solute b2a its vapour pressure becomes

Answer 1

Given that p°a = 0.80 ATM

and Pa = 0.60 ATM

we know that,

(p°a - Pa)/p°a = Xb

[.80 - .60]/0.8 = Xb

0.2/.8 =Xb

Xb =. 1/4