Question

the vapour pressure of pure liquid a is 0.80 atm on mixing non volatile b to a its vapour pressure becomes 0.6 atm the mole fraction of b in the soolution

Answer 1

given that p°a = 0.80 ATM


and Pa = 0.60 ATM


we know that,

(p°a - Pa)/p°a = Xb


[.80 - .60]/0.8 = Xb

0.2/.8 =Xb

Xb =. 1/4



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