the vapour pressure of pure liquid a is 0.80 atm on mixing non volatile b to a its vapour pressure becomes 0.6 atm the mole fraction of b in the soolution
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given that p°a = 0.80 ATM
and Pa = 0.60 ATM
we know that,
(p°a - Pa)/p°a = Xb
[.80 - .60]/0.8 = Xb
0.2/.8 =Xb
Xb =. 1/4
hope it helpful for you
please mark it as brainliest answer if you have satisfied
and Pa = 0.60 ATM
we know that,
(p°a - Pa)/p°a = Xb
[.80 - .60]/0.8 = Xb
0.2/.8 =Xb
Xb =. 1/4
hope it helpful for you
please mark it as brainliest answer if you have satisfied
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