Chemistry, asked by doifodeanand5, 2 months ago

The vapour pressure of pure water at 25°C is 18 mm Hg. When a
nonelectrolyte is dissolved, its vapour pressure becomes 17.32 mm Hg.
What is the relative lowering of vapour pressure of the solution?

Answers

Answered by shraddha663
4

Explanation:

its vapour pressure becomes 17.32 mm Hg. What is the relative lowering of vapour pressure of the solution ? M = 58.82 g/mol. Hence, the molecular weight of the solute is 58.82 g/mol.

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