Question

The vapour pressure of pure water at 250C is 18 mm Hg. When a non electrolyte is dissolved , its vapour pressure becomes 17.32 mm Hg. what is the relative lowering of vapour pressure of the solution ?

Answer 1

Answer:

The relationship between the relative lowering of vapour pressure and the molecular weight of solute and solvent is as shown below :

P

ΔP

=

M

W

×

w

m

Substitute values in the above expression :

23.76

23.76−23.32

=

M

5.40

×

90.0

18

M = 58.82 g/mol.

Hence, the molecular weight of solute is 58.82 g/mol.

Answer 2

its vapour pressure becomes 17.32 mm Hg. What is the relative lowering of vapour pressure of the solution ? M = 58.82 g/mol. Hence, the molecular weight of the solute is 58.82 g/mol.

please mark my ans as brainliest please