Question

The vapour pressure of pure water is 760 at 25 ,the vapour pressure of solution containing 1m solution od glucose will be

Answer 1

Heya Friend :-
We know the formula for lowering the vapor pressure 

(p⁰ -p) /p⁰ = (W₂/M₂ ) ₓ (M₁/W₁)
here p⁰ is the vapor pressure of pure sol.
p is the pressure of pure solvent.
now put the value in the formula.
(p⁰ -p) /p⁰ = M₁ x m
760-p/760 = 1 x 10⁻³ x 18

p = 746.32 nm.


I expect this helps you.