The vapour pressure of water and methyl alcohol are 30 and 50 mm of Hg Respectively. Calculate the total pressure of solution if 90 gm of water is mixed with 16 gm of methyl alcohol.
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Answer:
Mol. mass of ethyl alcohol =C
2
H
5
OH=46
No. of moles of ethyl alcohol =
46
60
=1.304
Mol. mass of methyl alcohol =CH
3
OH=32
No. of moles of methyl alcohol =
32
40
=1.25
′
X
A
′
, mole fraction of ethyl alcohol =
1.304+1.25
1.304
=0.5107
′
X
B
′
, mole fraction of methyl alcohol =
1.304+1.25
1.25
=0.4893
Partial pressure ethyl alcohol =X
A
p
˙
A
0
=0.5107×44.5=22.73mmHg
Partial pressure methyl alcohol =X
B
p
˙
B
0
=0.4893×88.7=73.40mmHg
Total vapour pressure of solution =22.73+43.40=66.13mmHg
Mole fraction of methyl alcohol in the vapour
=
Total vapour pressure
Partial pressure of CH
3
OH
=
66.13
43.40
=0.6563
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