The vapour pressure of water at room temperature
is 23.8 mm of Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to :
(1) 23.9 mm Hg
(2) 24.2 mm Hg
(3) 21.42 mm Hg
(4) 31.44 mm Hg
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ANSWER : C
Explanation:
P°-Ps/P° = Xsolute ( P° = vapour pressure of pure solvent , Ps = pressure of sucrose solution)
== 23.8-Ps/23.8 = 0.1
==23.8-Ps= 2.38
== Ps =21.42 mm of hg
== Ps=21.42mm of hg
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