Science, asked by Anonymous, 3 months ago

The vapour pressure of water at room temperature
is 23.8 mm of Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to :

(1) 23.9 mm Hg
(2) 24.2 mm Hg
(3) 21.42 mm Hg
(4) 31.44 mm Hg

DON'T SPAM❌​

Answers

Answered by chemistrywala
6

ANSWER : C

Explanation:

-Ps/ = Xsolute ( = vapour pressure of pure solvent , Ps = pressure of sucrose solution)

== 23.8-Ps/23.8 = 0.1

==23.8-Ps= 2.38

== Ps =21.42 mm of hg

== Ps=21.42mm of hg

HOPE IT WILL HELP YOU

Similar questions