. The vapour pressure of water is 12.3 kPa at 300 K Calculate vapour pressure of 1 molar solution of a solute in it.
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The vapour pressure of water is 12.3 kPa at 300 K. We need to calculate the vapour pressure of 1 molal solution of a non-volatile solute in it.
1000 g of water contains 1 mole of solute.
The molar mass of water is 18 g/mol.
Number of moles of water =181000=55.56 mol
Mole fraction of the solute in the solution is x=1+55.561=0.0177.
The relative lowering in the vapour pressure is equal to the mole fraction of solute.
p0p0−p=x
12.312.3−p=0.0177
⇒p=12.08
Hence, the vapour pressure of the solution is 12.08 kPa.
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