Question

The vapour pressure of water is 12.3 pascal calculate the vapour pressure of 1 molar solution

Answer 1

Hey mate here's your answer

Vapour pressure of pure water = 12.3 kPa

We have 1 molal solution that means we have 1 moles of solute in 1kg of solvent.

The formula of vapour pressure when non-volatile liquid is added,

Pressure (P) = vapour pressure of pure liquid P(pure) × molar fraction of liquid (X)

And we have mass = 1 kg and 1 kg is equal to 1000 g

And molar mass of water H2O = 2×1 + 16 = 18 g/mol

Number of moles of water =1000 g / (18g/mol ) =55.56 moles

The formula of molar fraction =55.5/(55.5+1) = 0.9823

Partial fraction = 12.3×0.9823 = 12.08

Answer 2

Answer:

REFER THE ATTACHMENT GIVEN ABOVE