Question

The vapour pressureof an aqua solution of sugar is 756 mm of HG how many grams of sugar present in the vapour pressure of pure water 760 mm of HG

Answer 1

Answer:

Explanation:

Relative lowering of vapor pressure is given by -

∆p/p° = X2

(p-p°)/p° = W2.M1 / M2.W1

(p-p°)/p° = m.M1

(760-732)/760 = m × 18/1000

m = (28×1000)/(760×18)

m = 2.047 m

Elevation in boiling point is calculated by -

∆Tb = Kb.m

∆Tb = 0.52 × 2.047

∆Tb = 1.064 ℃

Boiling point of solution will be -

∆Tb = Tb' - Tb

Tb' = Tb + ∆Tb

Tb' = 100 + 1.064

Tb' = 101.064 ℃