Question

The vapour pressures of pure liquids A and B respectively are 600 torr and 500 torr. In a binary solution of A and B, mole fraction of A is 0.25 then total pressure of the solution (in torr) will be​

Answer 1

Given:

The vapour pressures of pure liquids A and B respectively are 600 torr and 500 torr. In a binary solution of A and B, mole fraction of A is 0.25.

To find:

Total vapour pressure?

Calculation:

The net vapour pressure can be found using the general equation as follows:

$\rm \: P =(P_{A}^{ \circ} \times \chi_{A} )+ (P_{B}^{ \circ} \times \chi_{B})$

$\rm \implies\: P =(600 \times 0.25)+ \{500 \times (1 - 0.25) \}$

$\rm \implies\: P =(600 \times 0.25)+ \{500 \times 0.75 \}$

$\rm \implies\: P =150 + 375$

$\rm \implies\: P = 525 \: torr$

So, net vapour pressure if solution is 525 torr.

Answer 2

The total pressure of the solution will be 525 torr

Explanation:

Given:

The vapour pressure of liquid A is 600 torr

The vapour pressure of liquid B is 500 torr

The mole fraction of a is 0.25

To find out:

The total pressure in the solution

Solution:

$P_A=600$ torr

$P_B=500$ torr

$X_A=0.25$

$X_B=1-0.25=0.75$

Thus, the total pressure in the solution

$P=P_AX_A+P_BX_B$

$\implies P=600\times 0.25+500\times 0.75$

$\implies P=150+375$

$\implies P=525$ torr

Hope this answer is helpful.

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