Question

The vapour pressures of pure liquids A and B respectively are 600 torr and 500 torr. In a binary solution of A and B, mole fraction of A is 0.25 then total pressure of the solution (in torr) will be


625
530
525
575

Answer 1

Answer:

The vapour pressure of two pure liquids, A and B that form an ideal solution are 300 and 800 torr respectively, at temperature T. A mixture of the vapour of A and B for which the mole fraction of A is 0.25 is slowly compressed at temperature T. Calculate (a) the composition of the first drop of the condensate.

Upto two decimal places and multiply the answer by 100.

Answer

Correct option is

A

Explanation:

Answer

Correct option is

A

11

Py

A

=P

A

o

x

A

------------------------------(1)

y

A

=0.25

P

A

o

=300 torr, P

B

o

=800 torr ---------------------------(2)

P=P

A

o

x

A

+P

B

o

(1−x

A

)

Putting value of P from equation (1) in (2), we get

1700×x

A

=800

Hence, x

A

=0.47

Answer 2

The total pressure of the solution will be 525 torr

Therefore, option (c) is correct.

Explanation:

Given:

The vapour pressure of liquid A is 600 torr

The vapour pressure of liquid B is 500 torr

The mole fraction of a is 0.25

To find out:

The total pressure in the solution

Solution:

$P_A=600$ torr

$P_B=500$ torr

$X_A=0.25$

$X_B=1-0.25=0.75$

Thus, the total pressure in the solution

$P=P_AX_A+P_BX_B$

$\implies P=600\times 0.25+500\times 0.75$

$\implies P=150+375$

$\implies P=525$ torr

Hope this answer is helpful.

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