Question

The vapour ressure of pure benzene at acertain temperature is 262 bar. At the same temperature, the vapour of a solution containing 2g of a non-volatile solute in 100g benzene is 256 bar.what is the molecular mass of the solute?​

Answer 1

Answer: 68.12 g/mol

Step by Step Explanation:

(p°- p) ÷ p°= W2M1 ÷ W1M2

p° = 262 bar = Vapour pressure of pure benzene.

p = 256 bar = Vapour pressure of solution

W1 = 100g = Mass of benzene

W2 = 2g = Mass of solute

M1 = 78g/mol = Molar mass of benzene

M2= Molar mass of solute

262 - 256 / 262 = 2 × 78 / 100 × M2

M2 = 68.12g/mol

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