Question

The variable x varies directly as y and x =80 when y is 160. What is y when x is 64

Answer 1

Answer:

if x directly varies with y and if x= 80 and y=160 then,

Step-by-step explanation:

if x= 64 then y will be 64×2 or 64+64 = 128. I think you will understand it easily.

Answer 2

The value of y = 128

Given :

The variable x varies directly as y and x = 80 when y is 160

To find :

The value of y when x is 64

Solution :

Step 1 of 2 :

Calculate constant of variation

Here it is given that variable x varies directly as y

$\sf y \propto x$

∴ y = kx - - - - - - (1)

Where k is constant of variation

Now x = 80 when y is 160.

Thus we get

160 = k × 80

⇒ k = 160/80

⇒ k = 2

So constant of variation = k = 2

So that Equation 1 becomes

y = 2x - - - - - - (2)

Step 2 of 2 :

Find value of y when x is 64

y = 2x - - - - - - (2)

Now x = 64 gives

y = 2 × 64

⇒ y = 128

Hence the value of y = 128

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