The variable x varies directly as y . When y is 10 , x is 3/2 . Find y when x is 9.
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Given:
- X is directly proportional to Y
- The value of Y when X is 3/2 = 10
To Find:
- The value of Y when x is 9.
Solution:
Since X∝Y, we can write
⇒ Y = KX → {equation 1}
Where "K" is the proportionality constant.
We have the values of X and Y and by using this we should find the value of "K". On substituting the values in equation 1 we get,
⇒ 10 = K*(3/2)
⇒ K = (2/3)*10 {multiplying the terms}
⇒ K = 20/3
Now we have the value of K, let us find the value of Y when X is 9. On substituting the values of X and K in equation 1 we get,
⇒ Y = (20/3)*9 {cancelling the divisible terms}
⇒ Y = 20*3 = 60 {multiplying the terms}
∴ The value of Y when X is 9 = 60.
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