Question

the variation of a particle moving along a straight path is as shown in the graph. Find the distance traveled by it 13s​

Answer 1

Answer:

distance upto 4 sec

distance (0φ1sec)=

2

1

×1×20=10m

(1−2sec)=20×(2−1)=20m

(2−3sec)=(3−2)×10+

2

1

(3−2)×(20−10)

=1×10+

2

1

×1×10=15m

(3−4sec)=(4−3)×10=10m

Total distance = 10+20+15+10=55m

Explanation:

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