Physics, asked by rajeswariprabakaran7, 14 hours ago

the variation of displacement with respect to time is given by x=t^3-3t^2+6 meter the velocity at particle at t=2 sec is​

Answers

Answered by BhaveshBeast
0

So dx/dt=v

Diffrentiating we get v=3t^2-6t

So at t =2 sec v=0m/s

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