Question

The variation of force acting on a body moving along x-axis varies with the position of a particle as shown in figure the body is in stable equilibrium at

Answer 1

x=x1  

x=x2

both x1 and x2

neither x1 nor x2

Answer : B

Solution :

When particle moves aways from the origin then at position x=x1 force is zero and at x>x1, force is positive (repulsive in nature) so particle moves further and does not return back to original position. i.e. the equilibrium is not stable. Similarly at position x=x2 force is zero and at x>x2, force is negative (attractive in nature) So particle returns back to original position i.e. The equilibrium is stable.

Answer 2

Explanation:

The answer will be by extrapolation

• As we extrapolate x1 the value of x become -ve but the value of F lies in the -ve y axis and it is stable eqm

• As we extrapolate x2 ,the value of x become +ve  but the value of F lies in the +ve y axis and it is unstable eqm

                  Hope you understand

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