Question

The variation of horizontal and vertical distances with time are given by y = 8t- 4.9t”, x = 6t with MKS units. Then, the
angle of projection is

Answer 1

Answer:

x=6t=vcosθt

y=8t−4.9t

2

=vsinθt−

2

1

gt

2

⇒ On comparing,

vcosθ=6

vsinθ=8

⇒tanθ=

3

4

θ=tan

−1

(

3

4

)