The variation of potential difference v with length l in case of two potentiometers x and y is shown in the fig. which one of these two will you prefer for comparing emf of two cells and why?
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The question is incomplete as the figure has not been given. So, I am giving an assumed answer based on a similar question on other websites.
The Potentiometer Y has a lesser potential gradient (V/l) than the Potentiometer X. The Potentiometer Y will need comparatively more length to measure the same potential difference. Therefore, it will be more accurate and sensitive. Hence, the Potentiometer Y will be prefered than the Potentiometer X.
The Potentiometer Y has a lesser potential gradient (V/l) than the Potentiometer X. The Potentiometer Y will need comparatively more length to measure the same potential difference. Therefore, it will be more accurate and sensitive. Hence, the Potentiometer Y will be prefered than the Potentiometer X.
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hope this will help you
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