Question

The variation of Pressure P with volume V for an ideal monoatomic gas during an adiabatic process is shown in the figure

Answer 1

Explanation:

This is an upright parabola, so the equation is P = kV

2

By Ideal gas equation,

P =

V

nRT

So,

V

nRT

= kV

2

nRT = kV

3

By first law,

dQ = dU + PdV

Let the heat capacity of the gas in this process be C, dQ = nC dT

for diatomic gas, C

v

=

2

5R

C= C

v

=

2

5R

+ C

v

=

3

R

= C

v

=

6

17R

Answer 2

Answer:

5 P / 2 V

Explanation:

Y(monoatomic)= 5/3