The variation of velocity of a particle moving along a straight line is as shown in the figure given below.The distance travelled by the particle in 5 s is (a) 60m (b)30m (c) 40 m (d) 50 m
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We know,
Distance travelled by an object is given by the area covered in a velocity time graph.
Here,
Distance covered = Area of trapezium OABC
=> 1/2×(sum of parallel side)×height
=>1/2×(1+5)×20
=>6×10
=>60
So, the correct option is a)60m
Distance travelled by the object in 5seconds = 60m
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