Question

The variation of velocity of a particle moving along a straight line is illustrated in the following figure.The distance covered by the particle in 4 seconds is: ​

Answer 1

Answer:

• 1)in 1st second

v=u+at

20=0+a×1

a=20m/s^2

now distance=10m

• 2) in 1 to 2second

distance=20m

• 3)in 2s to 3 sec

a=(20-10)/1 =10m/s^2

distance =(20-5 )m=15m

• 4)in 3rd to 4th sec

distance=10m

total distance =(10+20+15+10)

=55m