the vector A and B are such that vector A+vector B =vectorA-vector B
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the angle between two vectors
A
and
B
be
θ
So
|
A
+
B
|
2
=
|
A
|
2
+
|
B
|
2
+
2
|
A
|
|
B
|
cos
θ
Again
|
A
−
B
|
2
=
|
A
|
2
+
|
B
|
2
+
2
|
A
|
|
B
|
cos
(
180
−
θ
)
By the given condition
|
A
+
B
|
=
|
A
−
B
|
So
cos
θ
=
cos
(
180
−
θ
)
⇒
θ
=
180
−
θ
⇒
θ
=
90
∘
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