Question

The vector A is given as
À = 3i+3j
Find the angle which the vector makes with the positive y-axis:​

Answer 1

Step-by-step explanation:

its its your answer hope its helping you

Answer 2

Answer:

The angle between A and y-axis is tan⁻¹ (2/3)

Explanation:

\overrightarrow{A} = 2 \hat{i} + 3 \hat{j}

A

=2

i

^

+3

j

^

Now,

A = |\overrightarrow{A}|∣

A

∣ = √(2² + 3²) = √(4 + 9) = √(13)

Now, the cosine is given as:

cos β = (Adjacent side)/(Hypotenuse)

On substituting the values, we get,

cos β = 3/√(13)

Now, the sine is given as:

sin β = (Opposite side)/(Hypotenuse)

On substituting the values, we get,

sin β = 2/√(13)

Now, the angle between A and y axis is given as:

tan β = (Opposite side)/(Adjacent side)

On substituting the values, we get,

tan β = 2/3

∴ β = tan⁻¹ (2/3)