Question

The vector equation of the line passing through the point (-1, 5, 4) and
perpendicular to the plane z = 0 is ?

Answer 1

We have to find the vector equation of the line passing through the point (-1, 5, 4) and perpendicular to the plane z = 0.

Solution : the line passing through (-1, 5, 4) and perpendicular to the plane z = 0.

Equation of plane could be written as 0. x + 0. y + 1. z + 0 = 0 So normal of plane = (0, 0, 1)

the line will be parallel to normal of the plane.

so, line is parallel to (0, 0, 1)

so the equation of line , r = (-1, 5, 4) + λ(0, 0, 1)

= -i + 5j + 4k + λ(0i + 0j + k)

Therefore the required equation of the line is -i + 5j + 4k + λ(0i + 0j + k) in vector form.

Answer 2

Answer:

Step-by-step explanation:

thanks