Question

The vectors A→=3iˆ−2jˆ+kˆ, B→=iˆ−3jˆ+5kˆ and C→=2iˆ+jˆ−4kˆA→=3i^−2j^+k^, B→=i^−3j^+5k^ and C→=2i^+j^−4k^ form a​

Answer 1

Answer:

The diagonals are given by AB−BC=4i−2j+4k,AB+BC=2i−2j

These vectors have magnitudes 6 and 2

2

respectively, and their dot product is 12.

Therefore the angle between them is cos

−1

(6)(2

2

)

12

=cos

−1

2

1

=

4

π

or π minus this value i.e.3π/4