The vectors A and Bare such that |A+B|=|A-B|.the angle between two vector is
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0 degree is the correct answer. a+b=R. A-B=R. a + b is equal to R square but R is equal to under root A square + B square + 2 AB cosTHETA. ....(1) and A-B is equal to R but in ( A-B). R is equal to under root a square + b square -2 AB cos theta.............(2). SOLVING 1 AND 2. WE GET 2ABCOS theta /2ABCOS theta= 1=cos 0° HENSE ANGLE BETWEEN THEM IS 0°
omkar42:
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Answer:90°
Explanation:
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