Question

The vectors a=sin(t)i-cos(t)j and b=cos(t^2/4)i+ sin(t^2/4)j are orthogonal

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Firstly orthogonal is being perpendicular to each other

Second Dot product comes out to be ABCosx so that means our product is zero because cos90 is zero

Third that SinACosB+CosASinB=Sin(A+B)

Now when you do the dot product you r left with

[Sin(t).Cos(t^2/4)]+[Cos(t).Sin(t^2/4)]=0

Then use the trignometric formula

Sin(t+t^2/4)=0

Now Sin0=0

Thats why t+t^2/4=0

Therefore t=4