The vectors î+ 29+ 3k, a î+ 49+7 K. - 3 i-2)-5k are collinear,
2 is equal to
a) 3
(b) 4
(c) 5
(d) 6
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Given,
i+2j+3k , ai+4j+7k , -3i-2j-5k are collinear
then delta=0
1 2 3
a 4 7 =0
-3 2 -5
1(-20-14)-2(-5a+21)+3(2a+12)=0
-34+10a-42+6a+36=0
16a=40
a=5/2
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