the vectors of equal magnitude 5 unit have an angle 60degree between them . Find the magnitude
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Given that,
Two vectors of equal magnitude = a = b
a = 5 unit
b = 5 unit
Angle b/w them => 60°
R = a vector + b vector
So,
![= > r = \sqrt{ {a}^{2} + {b}^{2} + 2ab \cos(60) } \\ \\ = > r = \sqrt{ {5}^{2} + {5}^{2} + 2 \times 5 \times 5 \times \frac{1}{2} } \\ \\ = > r = \sqrt{25 + 25 + 25} \\ \\ = > r = \sqrt[]{75} \\ \\ = > r = \sqrt{5 \times 5 \times 3} \\ \\ = > r = 5 \sqrt{3} unit](https://tex.z-dn.net/?f=+%3D++%26gt%3B+r+%3D++%5Csqrt%7B+%7Ba%7D%5E%7B2%7D+%2B++%7Bb%7D%5E%7B2%7D+++%2B+2ab+%5Ccos%2860%29+%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+r+%3D+++%5Csqrt%7B+%7B5%7D%5E%7B2%7D++%2B++%7B5%7D%5E%7B2%7D++%2B+2+%5Ctimes+5+%5Ctimes+5+%5Ctimes++%5Cfrac%7B1%7D%7B2%7D+%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+r+%3D++%5Csqrt%7B25+%2B+25+%2B+25%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+r+%3D++%5Csqrt%5B%5D%7B75%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+r+%3D++%5Csqrt%7B5+%5Ctimes+5+%5Ctimes+3%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+r+%3D+5+%5Csqrt%7B3%7D+unit "= > r = \sqrt{ {a}^{2} + {b}^{2} + 2ab \cos(60) } \\ \\ = > r = \sqrt{ {5}^{2} + {5}^{2} + 2 \times 5 \times 5 \times \frac{1}{2} } \\ \\ = > r = \sqrt{25 + 25 + 25} \\ \\ = > r = \sqrt[]{75} \\ \\ = > r = \sqrt{5 \times 5 \times 3} \\ \\ = > r = 5 \sqrt{3} unit")
I hope it will help you
Thanks
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Given that,
Two vectors of equal magnitude = a = b
a = 5 unit
b = 5 unit
Angle b/w them => 60°
R = a vector + b vector
So,
I hope it will help you
Thanks
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
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