Question

the vectors of equal magnitude 5 unit have an angle 60degree between them . Find the magnitude

Answer 1

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Given that,

Two vectors of equal magnitude = a = b

a = 5 unit
b = 5 unit

Angle b/w them => 60°

R = a vector + b vector

So,

$= > r = \sqrt{ {a}^{2} + {b}^{2} + 2ab \cos(60) } \\ \\ = > r = \sqrt{ {5}^{2} + {5}^{2} + 2 \times 5 \times 5 \times \frac{1}{2} } \\ \\ = > r = \sqrt{25 + 25 + 25} \\ \\ = > r = \sqrt[]{75} \\ \\ = > r = \sqrt{5 \times 5 \times 3} \\ \\ = > r = 5 \sqrt{3} unit$


I hope it will help you

Thanks

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