The vectors vecA has a magnitude of 5 unit vecB has a magnitude of 6 unit and the cross product of vecA and vecB has a magnitude of 15 unit. Find the angle between vecA and vecB.
Answers
Answered by
0
Answer:
30°
Explanation:
A×B=ABsinQ
(5)(6)sinQ=15
sinQ=1/2
Q=30°
PLEASE MARK MY ANSWER AS BRAINLIEST
Answered by
0
Explanation:
you can understand by seeing the pic
please mark my answer as the brainliest one
Attachments:

Similar questions