Question

The velocities of three particle of masses 20kg, 30g and 50g are 10I,10j and 10k respectively. The velocity of the center of mass of the three particle is

Answer 1

$\huge\underline\purple{\sf ♢Answer}$

$\large{\boxed{\sf V_{COM}=10m/s}}$

$\huge\underline\purple{\sf ♢ Solution}$

Formula to calculate centre of mass of velocity is :-

$\large{♡}$$\large{\boxed{\sf V_{COM}={\frac{m_1v_1+m_2v_2+m_3v_3}{m_1+m_2+m_3}}}}$

Given :-

$\sf{m_1}$=20 kg

$\sf{m_2}$=30 kg

$\sf{m_3}$= 50 kg

$\sf{v_1}$= $\sf{10{\hat{i}}}$

$\sf{v_2}$=$\sf{10{\hat{j}}}$

$\sf{v_3}$=$\sf{10{\hat{k}}}$

To find :-

Velocity of the center of mass of the three particle$\sf{V_{COM}}$=?

________________________________

On putting value in the solution :-

$\large\implies{\sf {\frac{20 \times 10+30 \times 10+50 \times 10}{20+30+50}}}$

$\large\implies{\sf {\frac{200+300+500}{100}}}$

$\large\implies{\sf 10m/s}$

$\huge\red{♡}$$\large\red{\boxed{\sf V_{COM}=10m/s}}$

Answer 2

The velocity of the center of mass of the three particle is 10 m/s.

Explanation:

Given that,

Mass of three particles are 20kg, 30g and 50g. There velocities are 10i, 10j and 10k respectively. We need to find the velocity of the center of mass of the three particle. It is given by :

$v=\dfrac{m_1v_1+m_2v_2+m_3v_3}{m_1+m_2+m_3}\\\\v=\dfrac{20\times 10+30\times 10+50\times 10}{20+30+50}\\\\v=10\ m/s$

so, the velocity of the center of mass of the three particle is 10 m/s.

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Center of mass

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